NCERT Class 12 Chapter 2 Maths Inverse Trigonometric MCQ | Questions & Answers: Are you guys looking for a way to improve your knowledge about the NCERT Class 12 Chapter 2 Maths Inverse Trigonometric? then check out this article & attempt the quiz right away and finally check your score.

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1. Solve for x : {xcos(cot^-1 x) + sin(cot^-1 x)}2 = 5150

A. 12√

B. 152√

C. 2√2

D. 5√2

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2. What is the principal value of sec^-1[-1/2]

A. (A)

B. (B)

C. (C)

D. (D)

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3. sin^-1 (sin2π3) =

A. 2π3

B. π6

C. 4π3

D. π3

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4.

A. (a)

B. (b)

C. (c)

D. (d)

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5. Identify the graph above.

A. y = sin^-1x

B. y = cos^-1x

C. y = sin x

D. y = cos x

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6. sin^-1 (1 – x) – 2 sin^-1 x = π2 then x = ?

A. 0, 12

B. 1, 12

C. 12

D. 0

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7.

A. (a)

B. (b)

C. (c)

D. (d)

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8. Evaluate

A. π/3

B. π

C. 1

D. not defined

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9. tan^-1 √3 – sec^-1(-2)

A. π

B. –π3, 0

C. π3

D. 2π3

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10.

A. (a)

B. (b)

C. (c)

D. (d)

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11.

A. (A)

B. (B)

C. (C)

D. (D)

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12. sin(sec^-1 x + cosec^-1x) =

A. 1

B. -1

C. π2

D. π3

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13. If sin^-1(x² – 7x + 12) = nπ, ∀ n ∈ I, then x =

A. -2

B. 4

C. -3

D. 5

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14.

A. -1

B. 0

C. 1

D. 1/3

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15. tan^-1 13 + tan^-1 17 =

A. tan-1 4429

B. π2

C. 0

D. π4

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16. If cos^-1 x + sin^-1 x = π, then the value of x is

A. 32

B. 12√

C. 3√2

D. 23√

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17. The principal value of tan-1 1 is given by

A. π/2

B. π/3

C. π/6

D. π/4

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18. If sin,sup>-1 x – cos^-1 x = π6, then x =

A. 12

B. 3√2

C. −12

D. −3√2

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19. The principle value of sin,sup>-1 √32 is

A. 2π3

B. π6

C. π4

D. π3

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20. Value of  in the range of sin^-1x is

A. 3π/4

B. π/4

C. 7π/4

D. -π/4

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21. The value of the expression tan^-1(12cos^-12√5) is

A. 2 + √5

B. √5 – 2

C. √5+24

D. √5 + 2

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22. If tan^-1 (cot θ) = 2θ, then θ is equal to

A. π3

B. π4

C. π6

D. None of these

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23. The cosine function can be restricted to any interval of the type_______, for its inverse to exist

A. [nπ/2,(n+1) π/2]

B. (nπ,(n+1) π)

C. [nπ ,(n+1) π]

D. (nπ/2,(n+1) π/2)

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24. Simplified form of cos^-1 (4x³ – 3x)

A. 3 sin^-1x

B. 3 cos^-1x

C. π – 3 sin^-1x

D. None of these

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25. cot(π4 – 2cot^-1 3) =

A. 7

B. 6

C. 5

D. 5

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